by AuSmith » Sat Aug 09, 2008 3:43 pm
Our approach will be to find the vertical displacement and the horizontal displacement (the two green distances) separately. A clue is the funky looking shape (no readily available formulas) and the given [unparseable or potentially dangerous latex formula] mi vertical distance.
Vertical Displacement: Since both ships turn [unparseable or potentially dangerous latex formula], their vertical speeds are going to be the same, and they will remain [unparseable or potentially dangerous latex formula] mi apart vertically.
Horizontal Displacement: It's the same as finding the horizontal leg of a triangle. The ships will each travel [unparseable or potentially dangerous latex formula] mph to the left or right. Combining their velocities, we have [unparseable or potentially dangerous latex formula] mph.
When the two are [unparseable or potentially dangerous latex formula] mi apart, the vertical amount is still [unparseable or potentially dangerous latex formula] mi, so the vertical will be [unparseable or potentially dangerous latex formula] mi. Divide that by the relative horizontal velocity to get the time. [unparseable or potentially dangerous latex formula] hrs.
- Attachments
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- The ships courses (not to scale).
- 08I-37.GIF (4.94 KiB) Viewed 1648 times