A projectile's maximum vertical elevation is 57ft and it lands 250ft away. What is the angle of release relative to the ground?
Answer = .739 (Radians)
Can someone walk me through the steps necessary to solve this problem?
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Projectile Help
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Projectile Help
by moy2414 » Tue Mar 15, 2011 1:59 pm
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Re: Projectile Help
by moy2414 » Tue Mar 15, 2011 2:01 pm
Oh and it is question 08I-36 incase that information helps.
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Re: Projectile Help
by TFugere » Tue Mar 15, 2011 5:09 pm
max height = 1/4 * tan0 * max range
so, 57= 1/4 * tan0 * 250
then 0= tan-1(4*57/250) = .739 rad
so, 57= 1/4 * tan0 * 250
then 0= tan-1(4*57/250) = .739 rad
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