'11-'12 Geometry Study Guide

[FabensMath]

For this one, my formula works, but if they were to give you something like 2[Segment Area] = Rectangle Area, i don't know if you would just multiply a side of the equation by 2, maybe you can help me with this one.

10H-60

[FabensMath]

I believe that's all, HOORAY! I believe there's long solutions for all of these problems, but you just need to find or derive the quickest shortcuts. I [unparseable or potentially dangerous latex formula] the study guide because it gives you easy +25 points, which can make the difference between 1st and 2nd or State and no-State.

[nsguy1350]

I'm definitely going to study this. FREE POINTS!
I'm going to make my team study it as well :D

[nsguy1350]

[FabensMath]

[FabensMath]

Does it make sense?

[nsguy1350]

I have a couple things.
First, why did you substitute in [unparseable or potentially dangerous latex formula]? Also, if that is valid, then you can simplify [unparseable or potentially dangerous latex formula].
You don't need to assume R = 1, because you can just divide both sides by R squared. However, it's valid either way.
And yes, if the segment area is twice as much, I don't see the problem with multiplying the left side by two. Make sure you know which side to multiply though.

When you went from [unparseable or potentially dangerous latex formula] to [unparseable or potentially dangerous latex formula], I don't see why you made the [unparseable or potentially dangerous latex formula] substitution, or how you even got that. Seems a lot simpler to just use [unparseable or potentially dangerous latex formula] to me.

[FabensMath]

Wait...i'm getting 1.45 using your formula, is that right?

[nsguy1350]

Hmm... no it isn't. I didn't check. Don't worry, I checked all the other ones I posted though.
I need to know why you made that substitution though. I don't see where you got it from.

[FabensMath]

I think i should fix that, make a difference between the theta and another angle, i guess beta. I put it in terms of the angle i'm looking for, therefore the pi-2theta is used for the segment area, while just the theta is used on the other side of the equation for the area of the rectangle.

[nsguy1350]

[nsguy1350]

[FabensMath]

[nerualmusic]

[FabensMath]

Hold up mon ami, i'll PM you.