2012 Invitational D

[murali0298]

On #7 - the remainder question, I know that if I divide, I can find the answer but is there any other faster method for that question???

[darksaber21]

Not really, not that I know of. What you can do is just divide, subtract the whole number, leaving the fractional part, and then multiply it by what you divided by at the start to get the whole number. I don't know of a way faster than that really.

[007math]

HP has a built in remainder key.

[88bobcat]

[murali0298]

[007math]

On my HP 33s, it is the pink/purple on the percent key on the last column and second row.

On the TI-84 (Plus or Plus Silver), the new updated OS includes a remainder function in the math menu (located in the second tab, scroll down to "0")

On the TI-89 (regular or Titanium), the remainder function is in the math menu under the subheading "Number" and you'll see it as "A" when you scroll down.

I don't think the HP 32sii has it (correct me if I'm mistaken).

[nsguy1350]

The 83/84 and 89 have their respective mod/remainder functions. On the 89 (murali has one, and I don't have an 84 to provide directions with,) go to [2nd][MATH][1:NUMBER][9:mod(]
and type in mod(39812, 293 + 489) = 712. 83/84 should be similar. Note: Do not try this on huge numbers(thousands digit of [unparseable or potentially dangerous latex formula] is not the thousands digit of mod(that number, 10000). 89 only stores a certain number of digits in its numbers, so this will always give you zero, as it stores as abcdefg.......xyz000000000000000.....000, where that horrendous representation is the huge number.)