by Kurt » Wed May 23, 2007 2:15 pm
I doubt Dr. White will put any more questions about dates on there since he's been informed that the TI-89 has a date function.
But in general, any particular date one year, will fall one day later the next year (with the exception of a leap year, in which case it's two days later.) Or equivalently, a particular day will fall the date earlier the next year. [unparseable or potentially dangerous latex formula]
So if April 23, 2005 is a Saturday, then 5 years later it will be 6 days earlier (1 extra one because of the leap year). So April 17th. However, this is now the 3rd Saturday, so you need to add 7...so April 24th.
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If a number is divisible by 72, it's divisible by 9 and 8. Since you only look at the last 3 digits for divisibility by 8, you can quickly think about all 9 cases and see which one is divisible by 8. That tells that digit y is 4. So to find x, we check for divisibility by 9. The sum of the digits (mod 9) excluding x is 3...so x must be 6 for the number to be divisible by 9.
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[unparseable or potentially dangerous latex formula].
For x to be an integer, y must be a multiple of 4. Since x0...or x<0, y>0. So the only solutions have the form x,y<0. To see the limit for solutions, check y=x, or [unparseable or potentially dangerous latex formula]. So all x,y must be less than -40. However, for any y that is a multiple of 4, but less than -40...x will be an integer smaller than y, since the limit for equality is at -40. So there are an infinite number of solutions.