forum.virtualchallengemeets.com

Today I ran into this little abomination:

How many pairs of integers (x,y) will solve the equation 6x^2-3xy-13x+5y=-11?

I was able to find that the answer was two, the solutions being at x=1 and x=2 and their corresponding integer y-values, but I solved them through some off-the-wall calculator use that I don't care to explain. What I'm asking is the "proper" way of solving this.

Any takers?

Here is AuSmith's explaination of this problem.

Aha! Thank you! His method was actually very similar to my own, but it's good to see it drawn out cleanly. :)