'09 TMSCA #6

[nsguy1350]

12. A circle with a circumference of 8.9 cm is inscribed in a triangle. The area of the triangle is 17.0 sq cm. Find the perimeter of the triangle. (nearest tenth)
A. 24.0 cm
14. What is the remainder when [unparseable or potentially dangerous latex formula] is divided by 13?
E. 12
17. Suppose A,B, and C are positive integers such that [unparseable or potentially dangerous latex formula]. The value of [unparseable or potentially dangerous latex formula] equals:
There has to be some type of easy trick here. I think I just found it. You can subtract 4 from 34/7 to get A, which is 4, then you are left with 6/7. Then, flip that, 6/7, to flip the other side, which becomes [unparseable or potentially dangerous latex formula]. Subtract 1 to get B, and you get [unparseable or potentially dangerous latex formula], so C = 5. That gives the right answer of A. 1.45!
Thanks anyways :D. I tried something similar during the test, but nothing worked.
32. All the face cards and all of the spades are removed from a standard of 52 cards. The remaining cards are shuffled. Two cards are dealt face up. What is the probability that the first card is a red Ace and the second card is a club? (nearest tenth %)
E. 2.3%, I got D. 4.8%, but apparently that didn't work.
37. Traveling Tex rode a bus from Fife Station to Doole Station to pick up his new car. The bus traveled at an average speed of 70 mile per hour. He drove his new car back to Fife Station at an average speed of 55 miles per hour. The total travel time from Fife to Doole and back to Fife was 4 hours 12 minutes. How far is it between the two stations? (nearest mile)
Harmonic mean of rates, x 2 to account for back and forth, multiply by time to get distance?
D. 129 miles
Actually, I just checked and it worked! haha I guess I am making you guys' lives easier!

Did 53, missed 3, skipped 4 for a total of 312, by best of the series, and to top it off, on a Larry White test! I should become a force near Region and State...

[Salvadoramerican]

Fermat's little theorem thus 7^12mod(13)=1 so (7^12)^167*7^6mod(13)= 1*7^6mod(13)=12