forum.virtualchallengemeets.com
Your connection to the competitive math/science community. (Formerly texasmath.org)
parabola
2 posts
• Page 1 of 1
parabola
by Salvadoramerican » Mon Feb 13, 2012 1:08 pm
finding the equation of a parabola given 3 points, one x-intercept, y-intercept, and a any point
MacArthur HS-Irving
Region 1 5A
Officially retire: It was an honor to compete against Dominic Yurk and his school, Paschal High(I attended Freshmen year there), in Science, gave a good fight.
It was a pleasure to compete with everyone in math thanks guys
Region 1 5A
Officially retire: It was an honor to compete against Dominic Yurk and his school, Paschal High(I attended Freshmen year there), in Science, gave a good fight.
It was a pleasure to compete with everyone in math thanks guys
- Salvadoramerican
- Determined Spammer
- Posts: 171
- Joined: Thu Feb 02, 2012 8:49 am
Re: parabola
by bradp » Mon Feb 13, 2012 2:23 pm
Given three points (x1,y1), (x2,y2), and (x3,y3) on the parabola y=ax^2+bx+c, all three points must satisfy the parabola's equation:
y1 = ax1^2+bx1+c
y2=ax2^2+bx2+c
y3=ax3^2+bx3+c
we know the 'y's and 'x's, so it's a system of three equations with three unknowns. Solve for a,b,c
y1 = ax1^2+bx1+c
y2=ax2^2+bx2+c
y3=ax3^2+bx3+c
we know the 'y's and 'x's, so it's a system of three equations with three unknowns. Solve for a,b,c
- bradp
- Perfectionist
- Posts: 670
- Joined: Sat Oct 21, 2006 5:07 pm
- Location: Kwood
2 posts
• Page 1 of 1
Who is online
Users browsing this forum: No registered users and 1 guest