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trig problem
Posted:
Mon Feb 20, 2012 7:36 pm
by smeag
solve: 4cos^2x - 1 = 0
no intervals! please show your steps...
Re: trig problem
Posted:
Mon Feb 20, 2012 8:54 pm
by AuSmith
What do you mean by "no intervals"?
Re: trig problem
Posted:
Mon Feb 20, 2012 9:03 pm
by nsguy1350
I think I understand what you mean.
Anyways, [unparseable or potentially dangerous latex formula]
[unparseable or potentially dangerous latex formula]
[unparseable or potentially dangerous latex formula]
[unparseable or potentially dangerous latex formula]
[unparseable or potentially dangerous latex formula]
I hope that notation is right.
pi/3 or -pi/3, plus or minus 2n x pi, where n is an integer.
Re: trig problem
Posted:
Mon Feb 20, 2012 10:29 pm
by Capybara
or cosx = -1/2, which gives x = 2pi/3+2kpi or 4pi/3+2kpi
Re: trig problem
Posted:
Mon Feb 20, 2012 10:55 pm
by nsguy1350
Thanks, how did I not catch that?