2009 district q's

[smeag]

Please show how you obtained your answer for problems
11, 16, 22, 25, 26, 27, 34, 41, 42, 45, 56

thanks very much!

[smeag]

at least do some of them please!

[nsguy1350]

District 1 or 2?

[smeag]

district 1
oops!

[smeag]

please help district is coming up!

[nsguy1350]

11. There are 16 total plants. Find the probability of each three getting picked three times.
5/16 x 4/15 x 3/14
4/16 x 3/15 x 2/14
7/16 x 6/15 x 5/14
Add those up, multiply by 100, and that should give you the total.

16. Not 100% sure, but first find the circumference of the smaller circle: [unparseable or potentially dangerous latex formula]. Since you do 48 or these rotations per minute, multiply by 48 to get centimeters per minute.

22. Can't you just use the solver, then plug in x?

25. The largest multiple that will fit is 31 x 8. Therefore, you can just put in [unparseable or potentially dangerous latex formula].

26. As you can see, the cycle repeats every multiple of 8. 725 mod 8 equals 5. Find where 5 is, column E, and there you go.

27. The final shape is a box. Draw a rectangle 3 feet by 5 feet. Then, take out squares of side s from each corner. When folding up the cut sheet of metal, you'll see the volume of the box is [unparseable or potentially dangerous latex formula]. Find the maximum of that, then find [unparseable or potentially dangerous latex formula] to see the area that was taken out of the squares. Divide that by 15 (3 x 5) and multiply by 100% to get your percent.

34. Find the probability of each and multiply. [unparseable or potentially dangerous latex formula].

41. You're trying to make a 91% solution. You have 90% and 92.5%. 90% is 1% away, and 92.5% is 1.5% away. Therefore, you want 60% of the solution to be 90% and 40% to be 92.5%.
If the total is 500g, then 40% of that is 200g, which will be the weight of the fruit ade.

42. I believe the angle is the average of the two arc measures. That makes 60 = [unparseable or potentially dangerous latex formula].

45. Get the equation in the form [unparseable or potentially dangerous latex formula], where a is the larger of a and b. It follows that the focus length, c, can be found through the equation [unparseable or potentially dangerous latex formula] (for hyperbolas, it's just the pythagorean theorem.) The foci will then be along the major axis (whichever is associated with a, x or y, has the major axis). Then, the foci are located at h or k, depending on which has the major axis, plus or minus c.

56. AE + BE = diameter, so radius = half of the diameter = 8 1/5. CD is a radius, and CE is the radius minus BE, so using the Pythagorean theorem, you can find DE.

Sorry, I have a bunch of stuff to do, so I did not find exact solutions, show all the work, or do much LaTeX. Hope that helps!