by darksaber21 » Wed Jan 02, 2013 5:36 pm
I would test out possible points. It is not as tedious as you think, if you know what you're doing that is.
First, to find out how many points are possible when y = 1
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So, 6 possible points there. (2, 3, 4, 5, 6, and 7)
We continue when y = 2:
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So 4 possible points there (3, 4, 5, and 6)
When y = 3:
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So 3 possible points (4, 5, and 6)
When y = 4:
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So one possible point (5)
Add them all up, and we get 14 points total.
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The inequality can be rearranged to be:
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Since y needs to be less than x, we can start off with y = 1 and see how many x values within the interval (and greater than y) satisfies the inequality.
I really can't think of another way, yet.
Now I know the stakes, and I'm willing to show what I gots. I will see you all at state for the first and final time, so let's end the year with a bang! :)
MTHS - Class 5A, District VII, Region I