forum.virtualchallengemeets.com

What is the digit in the tens place of 13^2006?

The answer is 9.

qwerty is right.

[unparseable or potentially dangerous latex formula]

[unparseable or potentially dangerous latex formula]

[unparseable or potentially dangerous latex formula]

[unparseable or potentially dangerous latex formula]

I can't immediately see an elegant solution, though one might exist.

Here's another possible solution, though it's still not exactly elegant. It involves the binomial expansion.

13^2006 = (10 + 3)^2006 = 10^2006 + 2006 * 3 * 10^2005 + ... + 2006 * 3^2005 * 10 + 3^2006.

Only the last 2 terms are relevant. The only problem is dealing with those massive powers of 3. This is why the solution still isn't elegant. The last two digits of the powers of 3 repeat every 20 powers(figuring this out take a long time, and it isn't fun writing 20 powers of 3), so 3^2005 is equivalent to 3^5 and 3^2006 is equivalent to 3^6. From here, the calculations are simple, giving you 9.

What test was this on, by the way? This seems like a ridiculously long problem.