by darksaber21 » Sat Jun 16, 2012 12:08 pm
If the integers are all in a sequence, and all add up to 360, then we can formulate:
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Since we need a to be an integer, we start plugging in values in multiples of two. That's what I did anyway. Eventually, you'll hit negative numbers, so plug numbers for multiples of two for d until that occurs, so you can find the smallest number, which happens to be:
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Plug in a six for d, and you will get -3, so plug in a four to get your answer.
Now I know the stakes, and I'm willing to show what I gots. I will see you all at state for the first and final time, so let's end the year with a bang! :)
MTHS - Class 5A, District VII, Region I