AMC 12 #20 1995

[stupidityismygam]

If [unparseable or potentially dangerous latex formula] and [unparseable or potentially dangerous latex formula] are three (not necessarily different) numbers chosen randomly and with replacement from the set [unparseable or potentially dangerous latex formula] the probability that [unparseable or potentially dangerous latex formula] is even is

[unparseable or potentially dangerous latex formula]
[unparseable or potentially dangerous latex formula]
[unparseable or potentially dangerous latex formula]
[unparseable or potentially dangerous latex formula]
[unparseable or potentially dangerous latex formula]

[bradp]

your answer formatting rocks


















not

[stupidityismygam]

[bradp]

the replacement makes this an ez problem
Clearly, we can do some case work:

a is even, b is odd ---> c is even
[unparseable or potentially dangerous latex formula]
a is even, b is even ---> c is even
[unparseable or potentially dangerous latex formula]
a is odd, b is even -----> c is even
[unparseable or potentially dangerous latex formula]
a is odd, b is odd ----> c is odd
[unparseable or potentially dangerous latex formula]

[unparseable or potentially dangerous latex formula]

[unparseable or potentially dangerous latex formula]

[unparseable or potentially dangerous latex formula]

[stupidityismygam]

paridy is my hero :) :)

[bradp]

I'm gonna rock the AMC next year.

[stupidityismygam]

go go power ranger...

get a 150 :) :)

[AuSmith]

Or you could combine the first three cases into one, namely when a and b are not both odd. 25-9=16

[zefuri]

glhf