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AMC 12 #20 1995
Posted:
Sun Apr 22, 2007 5:35 pmby stupidityismygam
If [unparseable or potentially dangerous latex formula] and [unparseable or potentially dangerous latex formula] are three (not necessarily different) numbers chosen randomly and with replacement from the set [unparseable or potentially dangerous latex formula] the probability that [unparseable or potentially dangerous latex formula] is even is
[unparseable or potentially dangerous latex formula]
[unparseable or potentially dangerous latex formula]
[unparseable or potentially dangerous latex formula]
[unparseable or potentially dangerous latex formula]
[unparseable or potentially dangerous latex formula]
Posted:
Sun Apr 22, 2007 5:36 pmby bradp
your answer formatting rocks
not
Posted:
Sun Apr 22, 2007 5:37 pmby stupidityismygam
Posted:
Sun Apr 22, 2007 6:06 pmby bradp
the replacement makes this an ez problem
Clearly, we can do some case work:
a is even, b is odd ---> c is even
[unparseable or potentially dangerous latex formula]
a is even, b is even ---> c is even
[unparseable or potentially dangerous latex formula]
a is odd, b is even -----> c is even
[unparseable or potentially dangerous latex formula]
a is odd, b is odd ----> c is odd
[unparseable or potentially dangerous latex formula]
[unparseable or potentially dangerous latex formula]
[unparseable or potentially dangerous latex formula]
[unparseable or potentially dangerous latex formula]
Posted:
Sun Apr 22, 2007 6:07 pmby stupidityismygam
paridy is my hero :) :)
Posted:
Sun Apr 22, 2007 6:14 pmby bradp
I'm gonna rock the AMC next year.
Posted:
Sun Apr 22, 2007 6:17 pmby stupidityismygam
go go power ranger...
get a 150 :) :)
Posted:
Sun Apr 22, 2007 6:21 pmby AuSmith
Or you could combine the first three cases into one, namely when a and b are not both odd. 25-9=16
Posted:
Sun Apr 22, 2007 9:33 pmby zefuri
glhf