by darksaber21 » Sun Jan 20, 2013 1:27 pm
We are looking for the number of combinations, which is the number of permutations over the number of possible arrangements of one permutation, right? Well, if we need at least one boy and one girl, then we have 6 possibilities for one spot, and 4 for another. Then, it doesn't matter who obtains the other two seats, so 8 different possible people for the third, and 7 for the fourth (as two or three people have been chosen before choosing the third or fourth spot respectively). So, assuming I did the math right:
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Now I know the stakes, and I'm willing to show what I gots. I will see you all at state for the first and final time, so let's end the year with a bang! :)
MTHS - Class 5A, District VII, Region I